$A$ closed vessel has a small hole in one face near the bottom,as shown in the figure. The velocity of water coming out from the hole at the given instant is ....... $m/s$. (Given: $P_{0} = 10^{5} \text{ N/m}^{2}$,$h = 9/4 \text{ m}$,density of water $\rho = 10^{3} \text{ kg/m}^{3}$,$g = 10 \text{ m/s}^{2}$)

Water is filled in a tank up to a height of $20 \ cm$ from the bottom of the tank. Water flows through a hole of area $1 \ mm^2$ at its bottom. The mass of the water coming out from the hole in a time of $0.6 \ s$ is (Density of water $= 1000 \ kg \ m^{-3}$ and acceleration due to gravity $= 10 \ m \ s^{-2}$) (in $g$)

$A$ large storage tank, open to the atmosphere at the top and filled with water, develops a small hole in its side at a point $20.0 \ m$ below the water level. If the rate of flow from the hole is $3.08 \times 10^{-5} \ m^3 s^{-1}$, then the diameter of the hole is (Take $g = 10 \ m s^{-2}$): (in $mm$)

$A$ large vessel with a small hole at the bottom is filled with water and kerosene, with kerosene floating on water. The length of the water column is $20 \,cm$ and that of the kerosene is $25 \,cm$. The velocity with which water flows out of the hole is (density of kerosene $= 0.8 \,g/cm^3$, density of water $= 1.0 \,g/cm^3$, neglect viscous force). (in $\,m/s$)

$A$ liquid is filled in a tank up to a height of $5 \,m$ and the bottom of the tank is at $5 \,m$ height from the ground. $A$ hole is punched in the tank so that the liquid coming out touches the ground at maximum horizontal distance. Then, the maximum horizontal distance is (in $\,m$)

$A$ light cylindrical vessel is kept on a horizontal surface. The area of the base is $A$. $A$ hole of cross-sectional area $a$ is made just at its bottom side. The minimum coefficient of friction necessary to prevent the vessel from sliding due to the impact force of the emerging liquid is $(a \ll A)$.